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Quadratic Function

The quadratic function is one of the most important functions in algebra. Its graph — the parabola — appears everywhere, from projectile motion to optimization problems.

Standard Form

📐Definition — Quadratic Function

A quadratic function has the form:

f(x)=ax2+bx+c,a0f(x) = ax^2 + bx + c, \quad a \neq 0

  • If a>0a > 0, the parabola opens upward.
  • If a<0a < 0, the parabola opens downward.
  • The larger a|a| is, the narrower the parabola.

Axis of Symmetry and Vertex

Theorem — Vertex Coordinates

For f(x)=ax2+bx+cf(x) = ax^2 + bx + c, the axis of symmetry is:

x=b2ax = -\frac{b}{2a}

The vertex is:

(b2a,  cb24a)\left(-\frac{b}{2a},\; c - \frac{b^2}{4a}\right)

The vertex gives the global minimum if a>0a > 0, or the global maximum if a<0a < 0.

Vertex Form

The vertex form is:

f(x)=a(xh)2+kf(x) = a(x - h)^2 + k

where (h,k)(h, k) is the vertex. To convert from standard form, complete the square.

Example — Completing the Square

Convert f(x)=x26x+5f(x) = x^2 - 6x + 5 to vertex form.

Solution.

f(x)=x26x+5=(x26x+9)9+5=(x3)24f(x) = x^2 - 6x + 5 = (x^2 - 6x + 9) - 9 + 5 = (x - 3)^2 - 4

The vertex is (3,4)(3, -4). The axis of symmetry is x=3x = 3.

f(x) = x² + +
a = 1.0
b = 0.0
c = 0.0
D = b²-4ac = 0.00Vertex: (0.00, 0.00)Roots: 0.00

The Discriminant and xx-intercepts

The xx-intercepts are the solutions of ax2+bx+c=0ax^2 + bx + c = 0. Their existence depends on the discriminant:

D=b24acD = b^2 - 4ac

DiscriminantRootsGraph
D>0D > 0Two distinct: x=b±D2ax = \dfrac{-b \pm \sqrt{D}}{2a}Crosses xx-axis twice
D=0D = 0One repeated: x=b2ax = -\dfrac{b}{2a}Touches xx-axis at vertex
D<0D < 0No real rootsDoes not cross xx-axis

Worked Example

Example — Complete Analysis

Find the vertex, axis of symmetry, and xx-intercepts of f(x)=2x24x6f(x) = 2x^2 - 4x - 6.

Solution.

Vertex: x=422=1x = -\dfrac{-4}{2 \cdot 2} = 1,   f(1)=246=8\;f(1) = 2 - 4 - 6 = -8. Vertex: (1,8)(1, -8).

Axis of symmetry: x=1x = 1.

Discriminant: D=(4)24(2)(6)=16+48=64>0D = (-4)^2 - 4(2)(-6) = 16 + 48 = 64 > 0.

Roots: x=4±84x = \dfrac{4 \pm 8}{4}, giving x=3x = 3 and x=1x = -1.

The parabola opens upward (a=2>0a = 2 > 0), has a minimum of 8-8 at x=1x = 1, and crosses the xx-axis at (1,0)(-1, 0) and (3,0)(3, 0).

Exercise

Find the vertex form and all intercepts of f(x)=x2+2x+3f(x) = -x^2 + 2x + 3.